nh4 2so4 naoh

To balance the equation (NH4)2SO4 + NaOH = Na2SO4 + NH3 + H2O using the algebraic method step-by-step, you must have experience solving systems of linear equations. The most common methods are substitution/elimination and linear algebra, but any similar method will work.

Step 1: Label Each Compound With a Variable

Label each compound (reactant or product) in the equation with a variable vĩ đại represent the unknown coefficients.

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a (NH4)2SO4 + b NaOH = c Na2SO4 + d NH3 + f H2O

Step 2: Create a System of Equations

Create an equation for each element (N, H, S, O, Na) where each term represents the number of atoms of the element in each reactant or product.

N:	2a	+	0b	=	0c	+	1d	+	0f
H:	8a	+	1b	=	0c	+	3d	+	2f
S:	1a	+	0b	=	1c	+	0d	+	0f
O:	4a	+	1b	=	4c	+	0d	+	1f
Na:	0a	+	1b	=	2c	+	0d	+	0f

Step 3: Solve For All Variables

Use substitution, Gaussian elimination, or a calculator vĩ đại solve for each variable.

  • 2a - 1d = 0
  • 8a + 1b - 3d - 2f = 0
  • 1a - 1c = 0
  • 4a + 1b - 4c - 1f = 0
  • 1b - 2c = 0

Use your graphing calculator's rref() function (or an online rref calculator) vĩ đại convert the following matrix into reduced row-echelon-form:

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[ 2	 0	 0	-1	 0	0]
[ 8	 1	 0	-3	-2	0]
[ 1	 0	-1	 0	 0	0]
[ 4	 1	-4	 0	-1	0]
[ 0	 1	-2	 0	 0	0]

The resulting matrix can be used vĩ đại determine the coefficients. In the case of a single solution, the last column of the matrix will contain the coefficients.

Simplify the result vĩ đại get the lowest, whole integer values.

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  • a = 1 ((NH4)2SO4)
  • b = 2 (NaOH)
  • c = 1 (Na2SO4)
  • d = 2 (NH3)
  • f = 2 (H2O)

Step 4: Substitute Coefficients and Verify Result

Count the number of atoms of each element on each side of the equation and verify that all elements and electrons (if there are charges/ions) are balanced.

(NH4)2SO4 + 2 NaOH = Na2SO4 + 2 NH3 + 2 H2O

Reactants Products
N22✔️
H1010✔️
S11✔️
O66✔️
Na22✔️

Since there is an equal number of each element in the reactants and products of (NH4)2SO4 + 2NaOH = Na2SO4 + 2NH3 + 2H2O, the equation is balanced.