6Cl + 6KOH → 5KCl + KClO_{3} + 3H_{2}O

⬇ Scroll down vĩ đại see reaction info and a step-by-step answer, or balance another equation.

Bạn đang xem: koh + cl

### Word Equation

Chlorine + Potassium Hydroxide = Potassium Chloride + Potassium Chlorate + Water

Six moles of _{3}]_{2}O]

### Reactants

### Chlorine - Cl

Element 17

### Potassium Hydroxide - KOH

E525 Potash Lye Potassium Hydrate Lye Caustic Potash Koh

### Products

### Potassium Chloride - KCl

Chlorid Draselny K-Tab Monopotassium Chloride Kcl Klor-Con Kaon-Cl 10 Chloride Of Potash Kaliumchlorid

### Potassium Chlorate - KClO

_{3}### Water - H

_{2}OHydroxic Acid H₂O [Oh2] Aqua Pure Water Hydrogen Oxide Oxidane Dihydrogen Oxide

### Thermodynamics

Thermodynamics of the reaction can be calculated using a lookup table.

#### Is the Reaction Exothermic or Endothermic?

Cl (g) | 6 mol | 121.29416 kJ/mol | -727.76496 kJ |
---|---|---|---|

KOH (s) | 6 mol | -425.84752 kJ/mol | 2555.08512 kJ |

KCl (s) | 5 mol | -435.88912 kJ/mol | -2179.4456 kJ |

KClO_{3} (s) | 1 mol | -391.204 kJ/mol | -391.204 kJ |

H_{2}O (g) | 3 mol | -241.818464 kJ/mol | -725.455392 kJ |

ΣΔH°_{f}(reactants) | -1827.32016 kJ | ||

ΣΔH°_{f}(products) | -3296.104992 kJ | ||

ΔH°_{rxn} | -1468.784832 kJ |

ΣΔH°_{f}(reactants) > ΣΔH°_{f}(products), so sánh Cl + KOH = KCl + KClO3 + H2O is **exothermic** (releases heat).

#### Is the Reaction Exoentropic or Endoentropic?

ΔS = S_{products} - S_{reactants}. If ΔS < 0, it is exoentropic. If ΔS > 0, it is endoentropic.

Cl (g) | 6 mol | 165.0588 J/(mol K) | -990.3528 J/K |
---|---|---|---|

KOH (s) | 6 mol | 78.8684 J/(mol K) | -473.2104 J/K |

KCl (s) | 5 mol | 82.67584 J/(mol K) | 413.3792 J/K |

KClO_{3} (s) | 1 mol | 142.96728 J/(mol K) | 142.96728 J/K |

H_{2}O (g) | 3 mol | 188.715136 J/(mol K) | 566.145408 J/K |

ΣΔS°(reactants) | 1463.5632 J/K | ||

ΣΔS°(products) | 1122.491888 J/K | ||

ΔS°_{rxn} | -341.071312 J/K |

ΣΔS°(reactants) > ΣΔS°(products), so sánh Cl + KOH = KCl + KClO3 + H2O is **exoentropic** (decrease in entropy).

#### Is the Reaction Exergonic or Endergonic?

ΔG = G_{products} - G_{reactants}. If ΔG < 0, it is exergonic. If ΔG > 0, it is endergonic.

Cl (g) | 6 mol | 105.31128 kJ/mol | -631.86768 kJ |
---|---|---|---|

KOH (s) | 6 mol | -379.0704 kJ/mol | 2274.4224 kJ |

KCl (s) | 5 mol | -408.31656 kJ/mol | -2041.5828 kJ |

KClO_{3} (s) | 1 mol | -289.90936 kJ/mol | -289.90936 kJ |

H_{2}O (g) | 3 mol | -228.588656 kJ/mol | -685.765968 kJ |

ΣΔG°(reactants) | -1642.55472 kJ | ||

ΣΔG°(products) | -3017.258128 kJ | ||

ΔG°_{rxn} | -1374.703408 kJ |

ΣΔG°(reactants) > ΣΔG°(products), so sánh Cl + KOH = KCl + KClO3 + H2O is **exergonic** (releases energy).

### Reaction Expressions

K_{c} or Q = ( [KCl]^{5} [KClO_{3}] [H_{2}O]^{3} ) / ( [Cl]^{6} [KOH]^{6} )

(assuming all reactants and products are aqueous. substitutue 1 for any solids/liquids, and Psubstance for gases.)

rate = -1/6 * (Δ[Cl] / Δt) = -1/6 * (Δ[KOH] / Δt) = 1/5 * (Δ[KCl] / Δt) = (Δ[KClO_{3}] / Δt) = 1/3 * (Δ[H_{2}O] / Δt)

(assuming constant volume in a closed system and no accumulation of intermediates or side products)

## Instructions

To balance a chemical equation, enter an equation of a chemical reaction and press the Balance button. The balanced equation will appear above.

- Use uppercase for the first character in the element and lowercase for the second character. Examples: Fe, Au, Co, Br, C, O, N, F.
- Ionic charges are not yet supported and will be ignored.
- Replace immutable groups in compounds vĩ đại avoid ambiguity. For example, C6H5C2H5 + O2 = C6H5OH + CO2 + H2O will not be balanced, but XC2H5 + O2 = XOH + CO2 + H2O will.
- Compound states [like (s) (aq) or (g)] are not required.
- You can use parenthesis () or brackets [].

## How vĩ đại Balance Chemical Equations

Read our article on how vĩ đại balance chemical equations or ask for help in our chat.

Balance any equation or reaction using this chemical equation balancer! Find out what type of reaction occured.

You can also ask for help or report an issue with the chemical equation balancer in our chat or forums.

## Balance Cl + KOH = KCl + KClO3 + H2O Using the Algebraic Method

Xem thêm: soạn văn 10 chân trời sáng tạo thần trụ trời

To balance the equation Cl + KOH = KCl + KClO3 + H2O using the algebraic method step-by-step, you must have experience solving systems of linear equations. The most common methods are substitution/elimination and linear algebra, but any similar method will work.

### Step 1: Label Each Compound With a Variable

Label each compound (reactant or product) in the equation with a variable vĩ đại represent the unknown coefficients.

a Cl + b KOH = c KCl + d KClO_{3} + f H_{2}O

### Step 2: Create a System of Equations

Create an equation for each element (Cl, K, O, H) where each term represents the number of atoms of the element in each reactant or product.

Cl: 1a + 0b = 1c + 1d + 0fK: 0a + 1b = 1c + 1d + 0fO: 0a + 1b = 0c + 3d + 1fH: 0a + 1b = 0c + 0d + 2f

### Step 3: Solve For All Variables

Use substitution, Gaussian elimination, or a calculator vĩ đại solve for each variable.

- 1a - 1c - 1d = 0
- 1b - 1c - 1d = 0
- 1b - 3d - 1f = 0
- 1b - 2f = 0

Use your graphing calculator's rref() function (or an online rref calculator) vĩ đại convert the following matrix into reduced row-echelon-form:

[ 1 0 -1 -1 0 0] [ 0 1 -1 -1 0 0] [ 0 1 0 -3 -1 0] [ 0 1 0 0 -2 0]

The resulting matrix can be used vĩ đại determine the coefficients. In the case of a single solution, the last column of the matrix will contain the coefficients.

Simplify the result vĩ đại get the lowest, whole integer values.

- a = 6 (Cl)
- b = 6 (KOH)
- c = 5 (KCl)
- d = 1 (KClO3)
- f = 3 (H2O)

### Step 4: Substitute Coefficients and Verify Result

Count the number of atoms of each element on each side of the equation and verify that all elements and electrons (if there are charges/ions) are balanced.

6 Cl + 6 KOH = 5 KCl + KClO_{3} + 3 H_{2}O

Cl | 6 | 6 | ✔️ |
---|---|---|---|

K | 6 | 6 | ✔️ |

O | 6 | 6 | ✔️ |

H | 6 | 6 | ✔️ |

Since there is an equal number of each element in the reactants and products of 6Cl + 6KOH = 5KCl + KClO3 + 3H2O, the equation is balanced.

## Balance Cl + KOH = KCl + KClO3 + H2O Using Inspection

The law of conservation of mass states that matter cannot be created or destroyed, which means there must be the same number atoms at the kết thúc of a chemical reaction as at the beginning. To be balanced, every element in Cl + KOH = KCl + KClO3 + H2O must have the same number of atoms on each side of the equation. When using the inspection method (also known as the trial-and-error method), this principle is used vĩ đại balance one element at a time until both sides are equal and the chemical equation is balanced.

### Step 1: Count the number of each element on the left and right hand sides

Reactants (Left Hand Side) | Products (Right Hand Side) | |||||||
---|---|---|---|---|---|---|---|---|

Reactants | Products | |||||||

Cl | KOH | Total | KCl | KClO_{3} | H_{2}O | Total | ||

Cl | 1 | 1 | 1 | 1 | 2 | ❌ | ||

K | 1 | 1 | 1 | 1 | 2 | ❌ | ||

O | 1 | 1 | 3 | 1 | 4 | ❌ | ||

H | 1 | 1 | 2 | 2 | ❌ |

### Step 2: Multiply coefficients for compounds vĩ đại balance out each element

For each element that is not equal, try vĩ đại balance it by adding more of it vĩ đại the side with less. Sometimes there may be multiple compounds with that element on one side, so sánh you'll need vĩ đại use your best judgement and be prepared vĩ đại go back and try the other options.

**Cl**is not balanced. Add**1**molecule of**Cl**vĩ đại the reactant (left-hand) side vĩ đại balance Chlorine:

2Cl + KOH = KCl + KClO_{3}+ H_{2}OReactants Products Cl 2 2 ✔️ K 1 2 ❌ O 1 4 ❌ H 1 2 ❌ **K**is not balanced. Add**1**molecule of**KOH**vĩ đại the reactant (left-hand) side vĩ đại balance Potassium:

2Cl + 2KOH = KCl + KClO_{3}+ H_{2}OReactants Products Cl 2 2 ✔️ K 2 2 ✔️ O 2 4 ❌ H 2 2 ✔️ **O**is not balanced. Add**2**molecules of**KOH**vĩ đại the reactant (left-hand) side vĩ đại balance Oxygen:

2Cl + 4KOH = KCl + KClO_{3}+ H_{2}OReactants Products Cl 2 2 ✔️ K 4 2 ❌ O 4 4 ✔️ H 4 2 ❌ **K**is not balanced. Add**2**molecules of**KCl**vĩ đại the product (right-hand) side vĩ đại balance Potassium:

2Cl + 4KOH = 3KCl + KClO_{3}+ H_{2}OReactants Products Cl 2 4 ❌ K 4 4 ✔️ O 4 4 ✔️ H 4 2 ❌ **Cl**is not balanced. Add**2**molecules of**Cl**vĩ đại the reactant (left-hand) side vĩ đại balance Chlorine:

4Cl + 4KOH = 3KCl + KClO_{3}+ H_{2}OReactants Products Cl 4 4 ✔️ K 4 4 ✔️ O 4 4 ✔️ H 4 2 ❌ **H**is not balanced. Add**1**molecule of**H**vĩ đại the product (right-hand) side vĩ đại balance Hydrogen:_{2}O

4Cl + 4KOH = 3KCl + KClO_{3}+ 2H_{2}OReactants Products Cl 4 4 ✔️ K 4 4 ✔️ O 4 5 ❌ H 4 4 ✔️ **O**is not balanced. Add**1**molecule of**KOH**vĩ đại the reactant (left-hand) side vĩ đại balance Oxygen:

4Cl + 5KOH = 3KCl + KClO_{3}+ 2H_{2}OReactants Products Cl 4 4 ✔️ K 5 4 ❌ O 5 5 ✔️ H 5 4 ❌ **K**is not balanced. Add**1**molecule of**KCl**vĩ đại the product (right-hand) side vĩ đại balance Potassium:

4Cl + 5KOH = 4KCl + KClO_{3}+ 2H_{2}OXem thêm: đoạn trích nữ oa thể hiện nội dung nào dưới đây

Reactants Products Cl 4 5 ❌ K 5 5 ✔️ O 5 5 ✔️ H 5 4 ❌

We could not determine all the steps needed vĩ đại balance the equation using trial and error. This may mean it requires too many steps and the chemical equation is too complex vĩ đại use this method, or that the equation is invalid (e.g. has 0 or non-integer coefficients). The algebraic method is likely better suited for balancing this equation.

If you would lượt thích vĩ đại attempt vĩ đại guess the next steps, the final element counts in the balanced equation should be:

6Cl + 6KOH = 5KCl + KClO_{3} + 3H_{2}O

Reactants | Products | ||
---|---|---|---|

Cl | 6 | 6 | ✔️ |

K | 6 | 6 | ✔️ |

O | 6 | 6 | ✔️ |

H | 6 | 6 | ✔️ |

## Bình luận