To balance the equation H2S + O2 = SO2 + H2O using the algebraic method step-by-step, you must have experience solving systems of linear equations. The most common methods are substitution/elimination and linear algebra, but any similar method will work.
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Step 1: Label Each Compound With a Variable
Label each compound (reactant or product) in the equation with a variable to tát represent the unknown coefficients.
a H2S + b O2 = c SO2 + d H2O
Step 2: Create a System of Equations
Create an equation for each element (H, S, O) where each term represents the number of atoms of the element in each reactant or product.
H: 2a + 0b = 0c + 2d S: 1a + 0b = 1c + 0d O: 0a + 2b = 2c + 1d
Step 3: Solve For All Variables
Use substitution, Gaussian elimination, or a calculator to tát solve for each variable.
- 2a - 2d = 0
- 1a - 1c = 0
- 2b - 2c - 1d = 0
Use your graphing calculator's rref() function (or an online rref calculator) to tát convert the following matrix into reduced row-echelon-form:
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[ 2 0 0 -2 0] [ 1 0 -1 0 0] [ 0 2 -2 -1 0]
The resulting matrix can be used to tát determine the coefficients. In the case of a single solution, the last column of the matrix will contain the coefficients.
Simplify the result to tát get the lowest, whole integer values.
- a = 2 (H2S)
- b = 3 (O2)
- c = 2 (SO2)
- d = 2 (H2O)
Step 4: Substitute Coefficients and Verify Result
Count the number of atoms of each element on each side of the equation and verify that all elements and electrons (if there are charges/ions) are balanced.
2 H2S + 3 O2 = 2 SO2 + 2 H2O
H | 4 | 4 | ✔️ |
---|---|---|---|
S | 2 | 2 | ✔️ |
O | 6 | 6 | ✔️ |
Since there is an equal number of each element in the reactants and products of 2H2S + 3O2 = 2SO2 + 2H2O, the equation is balanced.
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