c2h5oh c2h5ona

2C2H5OH + 2Na → 2C2H5ONa + H2

⬇ Scroll down to tướng see reaction info and a step-by-step answer, or balance another equation.

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Word Equation

Ethanol + Sodium = Sodium Ethanolate + Dihydrogen

C2H5OH + Na = C2H5ONa + H2 is a Single Displacement (Substitution) reaction where two moles of Ethanol [C2H5OH] and two moles of Sodium [Na] react to tướng form two moles of Sodium Ethanolate [C2H5ONa] and one mole of Dihydrogen [H2]

For pieces of sodium into the cup (test tube) containing ethyl alcohol → Having quit out air bubbles, melting pieces of sodium

Similarly water, ethyl alcohol effects with, freeing gases, such as hydrogen


  • Ethanol - C2H5OH

    Ethyl Alcohol Lux Dehydrated Ethanol 1-Hydroxyethane Spiritus Vini Methylcarbinol Hydroxyethane Alcohol (Ethyl)

  • Sodium - Na

    Natrium Element 11


  • Sodium Ethanolate - C2H5ONa

    Sodium Ethoxide Naoet Caustic Alcohol Ethoxysodium Sodium Ethylate

  • Dihydrogen - H2

    Molecular Hydrogen Hydrogen Molecule Hydrogen Hydrogen Gas Molecular Hydrogen Gas H₂

Reaction Expressions

Kc or Q = ( [C2H5ONa]2 [H2] ) / ( [C2H5OH]2 [Na]2 )

(assuming all reactants and products are aqueous. substitutue 1 for any solids/liquids, and Psubstance for gases.)

rate = -1/2 * (Δ[C2H5OH] / Δt) = -1/2 * (Δ[Na] / Δt) = một nửa * (Δ[C2H5ONa] / Δt) = (Δ[H2] / Δt)

(assuming constant volume in a closed system and no accumulation of intermediates or side products)


To balance a chemical equation, enter an equation of a chemical reaction and press the Balance button. The balanced equation will appear above.

  • Use uppercase for the first character in the element and lowercase for the second character. Examples: Fe, Au, Co, Br, C, O, N, F.
  • Ionic charges are not yet supported and will be ignored.
  • Replace immutable groups in compounds to tướng avoid ambiguity. For example, C6H5C2H5 + O2 = C6H5OH + CO2 + H2O will not be balanced, but XC2H5 + O2 = XOH + CO2 + H2O will.
  • Compound states [like (s) (aq) or (g)] are not required.
  • You can use parenthesis () or brackets [].

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Balance C2H5OH + Na = C2H5ONa + H2 Using the Algebraic Method

How To Balance C2H5OH + Na = C2H5ONa + H2

To balance the equation C2H5OH + Na = C2H5ONa + H2 using the algebraic method step-by-step, you must have experience solving systems of linear equations. The most common methods are substitution/elimination and linear algebra, but any similar method will work.

Step 1: Label Each Compound With a Variable

Label each compound (reactant or product) in the equation with a variable to tướng represent the unknown coefficients.

a C2H5OH + b Na = c C2H5ONa + d H2

Step 2: Create a System of Equations

Create an equation for each element (C, H, O, Na) where each term represents the number of atoms of the element in each reactant or product.

C:	2a	+	0b	=	2c	+	0d
H:	6a	+	0b	=	5c	+	2d
O:	1a	+	0b	=	1c	+	0d
Na:	0a	+	1b	=	1c	+	0d

Step 3: Solve For All Variables

Use substitution, Gaussian elimination, or a calculator to tướng solve for each variable.

  • 2a - 2c = 0
  • 6a - 5c - 2d = 0
  • 1a - 1c = 0
  • 1b - 1c = 0

Use your graphing calculator's rref() function (or an online rref calculator) to tướng convert the following matrix into reduced row-echelon-form:

[ 2	 0	-2	 0	0]
[ 6	 0	-5	-2	0]
[ 1	 0	-1	 0	0]
[ 0	 1	-1	 0	0]

The resulting matrix can be used to tướng determine the coefficients. In the case of a single solution, the last column of the matrix will contain the coefficients.

Simplify the result to tướng get the lowest, whole integer values.

  • a = 2 (C2H5OH)
  • b = 2 (Na)
  • c = 2 (C2H5ONa)
  • d = 1 (H2)

Step 4: Substitute Coefficients and Verify Result

Count the number of atoms of each element on each side of the equation and verify that all elements and electrons (if there are charges/ions) are balanced.

2 C2H5OH + 2 Na = 2 C2H5ONa + H2

Reactants Products

Since there is an equal number of each element in the reactants and products of 2C2H5OH + 2Na = 2C2H5ONa + H2, the equation is balanced.

Balance C2H5OH + Na = C2H5ONa + H2 Using Inspection

The law of conservation of mass states that matter cannot be created or destroyed, which means there must be the same number atoms at the kết thúc of a chemical reaction as at the beginning. To be balanced, every element in C2H5OH + Na = C2H5ONa + H2 must have the same number of atoms on each side of the equation. When using the inspection method (also known as the trial-and-error method), this principle is used to tướng balance one element at a time until both sides are equal and the chemical equation is balanced.

Step 1: Count the number of each element on the left and right hand sides

Reactants (Left Hand Side)Products (Right Hand Side)

Step 2: Multiply coefficients for compounds to tướng balance out each element

For each element that is not equal, try to tướng balance it by adding more of it to tướng the side with less. Sometimes there may be multiple compounds with that element on one side, so sánh you'll need to tướng use your best judgement and be prepared to tướng go back and try the other options.

  1. H is not balanced. Add 1 molecule of C2H5OH to tướng the reactant (left-hand) side to tướng try to tướng balance Hydrogen:
    2C2H5OH + Na = C2H5ONa + H2

  2. C is not balanced. Add 1 molecule of C2H5ONa to tướng the product (right-hand) side to tướng balance Carbon:
    2C2H5OH + Na = 2C2H5ONa + H2

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  3. Na is not balanced. Add 1 molecule of Na to tướng the reactant (left-hand) side to tướng balance Sodium:
    2C2H5OH + 2Na = 2C2H5ONa + H2


Step 3: Verify that the equation is balanced

Since there are an equal number of atoms of each element on both sides, the equation is balanced.

2C2H5OH + 2Na = 2C2H5ONa + H2

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