# al2o3 al2so43

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let bu know where is Al2O3 in Al2(SO4)3 containing from? as we know there is 17-18% Al2O3 in commonly Al2(SO4)3 product. is it because low convertion of reaction Al2O3 + 3H2SO4 = Al2(SO4)3 + 3H2O, or something?

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if i using Al(OH)3 đồ sộ convert Al2(SO4)3, 2Al(OH)3 + 3H2SO4 = Al2(SO4)3 + 6H2O, is it still happen 17-18% containing Al2O3 in Al2(SO3)3 because dehydration reaction of 2Al(OH)3 = Al2O3 + 3H2O?

AChem

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asked Apr 13, 2020 at 22:02

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You are referring đồ sộ very old analytical methods and analysis. In older times, many analyses were reported as oxides. This practice comes from gravimetric analysis. This practice continues today in fertilizers analysis and in some other industries. Coming đồ sộ your question, there is no Al$_2$O$_3$ unit per se however the purity of aluminum sulfate may be quoted as aluminum oxide. Just tự a simple mole calculation using the relation đồ sộ determine the actual purity of aluminium sulfate. Just keep in mind, quoting percentage of oxides is purely historical, but you can easily tự calculations as follows.

1 mol Al$_2$O$_3$ $\equiv$ 1 mol Al$_2$SO$_4$ $\equiv$ 1 mol Al$_2$SO$_4$. $x$H$_2$O

answered Apr 14, 2020 at 0:54

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